Optimal. Leaf size=78 \[ \frac {15}{4} b^2 \sqrt {a+b x}-\frac {15}{4} \sqrt {a} b^2 \tanh ^{-1}\left (\frac {\sqrt {a+b x}}{\sqrt {a}}\right )-\frac {(a+b x)^{5/2}}{2 x^2}-\frac {5 b (a+b x)^{3/2}}{4 x} \]
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Rubi [A] time = 0.02, antiderivative size = 78, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 4, integrand size = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.308, Rules used = {47, 50, 63, 208} \begin {gather*} \frac {15}{4} b^2 \sqrt {a+b x}-\frac {15}{4} \sqrt {a} b^2 \tanh ^{-1}\left (\frac {\sqrt {a+b x}}{\sqrt {a}}\right )-\frac {(a+b x)^{5/2}}{2 x^2}-\frac {5 b (a+b x)^{3/2}}{4 x} \end {gather*}
Antiderivative was successfully verified.
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Rule 47
Rule 50
Rule 63
Rule 208
Rubi steps
\begin {align*} \int \frac {(a+b x)^{5/2}}{x^3} \, dx &=-\frac {(a+b x)^{5/2}}{2 x^2}+\frac {1}{4} (5 b) \int \frac {(a+b x)^{3/2}}{x^2} \, dx\\ &=-\frac {5 b (a+b x)^{3/2}}{4 x}-\frac {(a+b x)^{5/2}}{2 x^2}+\frac {1}{8} \left (15 b^2\right ) \int \frac {\sqrt {a+b x}}{x} \, dx\\ &=\frac {15}{4} b^2 \sqrt {a+b x}-\frac {5 b (a+b x)^{3/2}}{4 x}-\frac {(a+b x)^{5/2}}{2 x^2}+\frac {1}{8} \left (15 a b^2\right ) \int \frac {1}{x \sqrt {a+b x}} \, dx\\ &=\frac {15}{4} b^2 \sqrt {a+b x}-\frac {5 b (a+b x)^{3/2}}{4 x}-\frac {(a+b x)^{5/2}}{2 x^2}+\frac {1}{4} (15 a b) \operatorname {Subst}\left (\int \frac {1}{-\frac {a}{b}+\frac {x^2}{b}} \, dx,x,\sqrt {a+b x}\right )\\ &=\frac {15}{4} b^2 \sqrt {a+b x}-\frac {5 b (a+b x)^{3/2}}{4 x}-\frac {(a+b x)^{5/2}}{2 x^2}-\frac {15}{4} \sqrt {a} b^2 \tanh ^{-1}\left (\frac {\sqrt {a+b x}}{\sqrt {a}}\right )\\ \end {align*}
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Mathematica [C] time = 0.01, size = 35, normalized size = 0.45 \begin {gather*} -\frac {2 b^2 (a+b x)^{7/2} \, _2F_1\left (3,\frac {7}{2};\frac {9}{2};\frac {b x}{a}+1\right )}{7 a^3} \end {gather*}
Antiderivative was successfully verified.
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IntegrateAlgebraic [A] time = 0.11, size = 68, normalized size = 0.87 \begin {gather*} \frac {\sqrt {a+b x} \left (15 a^2-25 a (a+b x)+8 (a+b x)^2\right )}{4 x^2}-\frac {15}{4} \sqrt {a} b^2 \tanh ^{-1}\left (\frac {\sqrt {a+b x}}{\sqrt {a}}\right ) \end {gather*}
Antiderivative was successfully verified.
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fricas [A] time = 1.04, size = 133, normalized size = 1.71 \begin {gather*} \left [\frac {15 \, \sqrt {a} b^{2} x^{2} \log \left (\frac {b x - 2 \, \sqrt {b x + a} \sqrt {a} + 2 \, a}{x}\right ) + 2 \, {\left (8 \, b^{2} x^{2} - 9 \, a b x - 2 \, a^{2}\right )} \sqrt {b x + a}}{8 \, x^{2}}, \frac {15 \, \sqrt {-a} b^{2} x^{2} \arctan \left (\frac {\sqrt {b x + a} \sqrt {-a}}{a}\right ) + {\left (8 \, b^{2} x^{2} - 9 \, a b x - 2 \, a^{2}\right )} \sqrt {b x + a}}{4 \, x^{2}}\right ] \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 1.12, size = 80, normalized size = 1.03 \begin {gather*} \frac {\frac {15 \, a b^{3} \arctan \left (\frac {\sqrt {b x + a}}{\sqrt {-a}}\right )}{\sqrt {-a}} + 8 \, \sqrt {b x + a} b^{3} - \frac {9 \, {\left (b x + a\right )}^{\frac {3}{2}} a b^{3} - 7 \, \sqrt {b x + a} a^{2} b^{3}}{b^{2} x^{2}}}{4 \, b} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.01, size = 61, normalized size = 0.78 \begin {gather*} 2 \left (\left (-\frac {15 \arctanh \left (\frac {\sqrt {b x +a}}{\sqrt {a}}\right )}{8 \sqrt {a}}+\frac {\frac {7 \sqrt {b x +a}\, a}{8}-\frac {9 \left (b x +a \right )^{\frac {3}{2}}}{8}}{b^{2} x^{2}}\right ) a +\sqrt {b x +a}\right ) b^{2} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 2.94, size = 101, normalized size = 1.29 \begin {gather*} \frac {15}{8} \, \sqrt {a} b^{2} \log \left (\frac {\sqrt {b x + a} - \sqrt {a}}{\sqrt {b x + a} + \sqrt {a}}\right ) + 2 \, \sqrt {b x + a} b^{2} - \frac {9 \, {\left (b x + a\right )}^{\frac {3}{2}} a b^{2} - 7 \, \sqrt {b x + a} a^{2} b^{2}}{4 \, {\left ({\left (b x + a\right )}^{2} - 2 \, {\left (b x + a\right )} a + a^{2}\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 0.05, size = 64, normalized size = 0.82 \begin {gather*} 2\,b^2\,\sqrt {a+b\,x}+\frac {7\,a^2\,\sqrt {a+b\,x}}{4\,x^2}-\frac {9\,a\,{\left (a+b\,x\right )}^{3/2}}{4\,x^2}+\frac {\sqrt {a}\,b^2\,\mathrm {atan}\left (\frac {\sqrt {a+b\,x}\,1{}\mathrm {i}}{\sqrt {a}}\right )\,15{}\mathrm {i}}{4} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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sympy [A] time = 4.30, size = 126, normalized size = 1.62 \begin {gather*} - \frac {15 \sqrt {a} b^{2} \operatorname {asinh}{\left (\frac {\sqrt {a}}{\sqrt {b} \sqrt {x}} \right )}}{4} - \frac {a^{3}}{2 \sqrt {b} x^{\frac {5}{2}} \sqrt {\frac {a}{b x} + 1}} - \frac {11 a^{2} \sqrt {b}}{4 x^{\frac {3}{2}} \sqrt {\frac {a}{b x} + 1}} - \frac {a b^{\frac {3}{2}}}{4 \sqrt {x} \sqrt {\frac {a}{b x} + 1}} + \frac {2 b^{\frac {5}{2}} \sqrt {x}}{\sqrt {\frac {a}{b x} + 1}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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